What are the possible sources of error in a calorimetry experiment?

The biggest source of error in calorimetry is usually unwanted heat loss to the surroundings. This can be reduced by insulating the sides of the calorimeter and adding a lid.

What is the experimental heat of fusion of ice?

The amount of heat that must be absorbed by a quantity of a solid to melt it is called the heat of fusion. In this lab, ice will be added to cool heated water from 50 ˚C to about 2–4 ˚C. The temperature difference is used to calcu- late the amount of energy lost as the water cooled (Equation 1).

Can heat of fusion of ice be negative?

The most common example is solid ice turning into liquid water. However, if the substance is transforming from a liquid state to a solid state the change in enthalpy (ΔH) is negative. This process is commonly known as the freezing, and results in the molecules within the substance becoming more ordered.

What was the error in heat of fusion?

Heat of Fusion Experimental Error: The source of error that could have occurred during this lab is heat could have been lost during transfer from the ice bin to the calorimeter: while dabbing it the paper towel gave some heat, the air around the specimen also melted the ice cube a little bit.

How is the latent heat of fusion of ice determined?

The purpose of this lab is to determine the Latent Heat of Fusion of ice. In this experiment the heat of fusion of ice will be determined by using the method of mixtures (Quantity of heat lost = Quantity of heat gained). When a solid has reached its melting point, additional heating melts the solid without a temperature change.

How is the heat of fusion for water determined?

In this lab, the heat of fusion for water will be determined by monitoring the temperature changes while a known mass of ice melts in a cup of water. The experimentally determined value for heat of fusion will be compared with the accepted standard value.

How is heat lost when Ice Cube melts?

The warm water in the cup loses heat to melt the ice and then to warm up the new cold water formed when the ice cube melts. The heat lost by the warm water can be calculated using the equation below: (Hsp = 1 cal/g ° C) Heat lost (warm water) = mw x Hsp x (Tw -Tfinal) (enter in row 9) 4.