What is the spring constant of rubber?

45.0N/m
Spring constant of the rubber band is k=45.0N/m.

How do you calculate the energy of a rubber band?

Elastic potential energy (measured in the unit joules) is equal to ½ multiplied by the stretch length (“x”) squared, multiplied by the spring constant “k.” The spring constant is different for every rubber band, but can be figured out (see “Welcome to the Guide to Shooting Rubber Bands” below).

How do you find the kinetic energy of a spring constant?

Identify the spring’s maximum kinetic energy, at the equilibrium point, as equal to the initial potential energy. Calculate the kinetic energy at any other point of displacement, X, by subtracting the potential energy at that point from the initial potential energy: KE = (0.5)kx^2 – (0.5)kX^2.

How much energy is in a rubber band?

The rubber band has a mass of 1.09 grams. This puts the specific energy at 1651 J/kg for stretching and 6605 J/kg for twisting.

What is the spring constant of a rubber band?

The spring constant is different for every rubber band, but can be figured out (see “Welcome to the Guide to Shooting Rubber Bands” below). When the rubber band is released, the potential energy is quickly converted to kinetic (motion) energy.

How is the elastic force of rubber different from a spring?

It is fundamentally different from the restoring force in a spring, which relies on the mechanical stiffness of the material. In rubber the elastic force is due to the thermal interactions of the molecules within the material. There are several molecular mechanisms that work together to produce the elastic force.

How is the spring constant related to the displacement?

The equation for elastic potential energy relates the displacement, ​ x ​, and the spring constant, ​ k ​, to the elastic potential ​ PE ​ el, and it takes the same basic form as the equation for kinetic energy: As a form of energy, the units of elastic potential energy are joules (J).

When is kinetic energy equal to spring energy?

So the kinetic energy of the mass is equal to the spring energy when we pull/push the mass and the spring pushes/pulls is back and when the mass is at equilibrium position? Reply to Pannaga Bhat’s post “So the kinetic energy of the mass is equal to the …”